Re: Another key analogy

Justin Dolske (dolske@cis.ohio-state.edu)
Fri, 18 Apr 1997 17:27:55 -0400 (EDT)


On Fri, 18 Apr 1997, Alex Bischoff wrote:

> Calculation
> ===================
> 2^57 / (3.70059448819 x 10^13) = 3894 times around the sun

Yup, looks fine to me. However, I don't know if this is very meaningful
for Joe Public. He tends to have a hard time telling what orbits,
rotations, and right-ascencions are. :-)

Here's another possibility:

384401 km ( 4e5) -- Mean Earth-Moon distance
= 1.513e10 inches
2**57 inches / 1.513e10 = 9.5 million trips to the moon and back.

Or:

6378 km (6400) -- Equatorial radius of Earth
= 2.511e8 inches
2**57 / 2.511e8 = 574 million trips around the earth

IMHO, these are still just Big Numbers.

Hmm, here's an idea:

SurfaceArea_Earth = 5.490e15 ft^2
2**56 / SA_E = 13 keys per square foot, if you spread them out evenly.

Or, 8.5 keys on a standard 8.5x11 sheet of paper.

Justin Dolske <URL:http://www.cis.ohio-state.edu/~dolske/>
(dolske@cis.ohio-state.edu)
Graduate Fellow / Research Associate at The Ohio State University, CIS Dept.
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